Someone answer this:
You have 32 teams, how many games are played in total if each team plays against every other team twice?
Me and J arrived at the same answer using different methods even though he thought my logic was flawed. We have PhD's, doctors, lawyers, bankers, designers, engineers, etc, i wanna see how each person comes up with the answer (edit) from scratch without looking up the formula.
9 comments:
The would be lawyer says: Use that combination formula and times the whole thing by 2.
2[n!/(k!(n-k)!)]
2[32!/(2!(32-2))!]
992
What'd you guys get?
Wait, I think I made a mistake. But I'm still pretty sure the answer involves those exclamation points.
1984!!! that was a good year.
just to second heids, I added the !!!
i used the matrix. neo-style.
2[(n^2)-n]
2[(32^2)-32]
2[1024-32]
2[992]
1984
J also used combination formula and got 992.
I broke it up into subsets:
{1,2}
{1,3}
..
{1,32}
{2,3}
{2,4}
..
{2,32}
..
{31,32}
That seems to give me 32*31 which is what your combination formula simplifies to.
Deja vu, I think there's a glitch in the matrix. There are repeat combinations in there.
oh yesh. you're right. there is a glitch. damn that Mr. Anderson.
Okay, take my equation and divide by 2.
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